2x^2-10/7x-5=0

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Solution for 2x^2-10/7x-5=0 equation: 


x in (-oo:+oo)

2*x^2-((10/7)*x)-5 = 0

2*x^2+(-10/7)*x-5 = 0

2*x^2-10/7*x-5 = 0

DELTA = (-10/7)^2-(-5*2*4)

DELTA = 2060/49

DELTA > 0

x = ((2060/49)^(1/2)+10/7)/(2*2) or x = (10/7-(2060/49)^(1/2))/(2*2)

x = ((2060/49)^(1/2)+10/7)/4 or x = (10/7-(2060/49)^(1/2))/4

x in { (10/7-(2060/49)^(1/2))/4, ((2060/49)^(1/2)+10/7)/4 }

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